The alkene shown is treated with ozone and then with $\mathrm{H}{}_2\mathrm{O}{}_2$. Which statements are correct?

The compound shown is (E)-4-methylpent-2-ene. Cleavage gives ethanal and 2-methylpropanal, and the oxidative work-up converts both aldehydes to ethanoic acid and 2-methylpropanoic acid. Neither carbon of the double bond is fully substituted, so no ketone forms, and the skeleton is branched, so butanoic acid is not produced.