The diene shown is treated with excess ozone and then with $\mathrm{H}{}_2\mathrm{O}{}_2$. Which pair of products is correct?

The compound shown is (2E,4E)-hexa-2,4-diene. Cleaving both double bonds gives two terminal $\mathrm{CH}{}_3\mathrm{CHO}$ units and a central $\mathrm{OHC}-\mathrm{CHO}$. Oxidative work-up converts ethanal to ethanoic acid and ethanedial to ethanedioic (oxalic) acid. The central unit is not the same compound as the terminal one, so ethanoic acid alone is not the answer.