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JEE Main levelSingle correct optionDifficulty 2 of 3hc116

Propyne is treated with $NaNH X_{2}$ in liquid ammonia and the product is then treated with bromoethane. The final organic product is

Abut-2-yne
Bpent-1-yne
Cpent-2-yne
Dpent-2-ene

Answer: C

NaNH X_{2}

forms

CH X_{3} - C \equiv C X^{-} Na X^{+}

, a nucleophile that displaces bromide from the primary halide (

SN X_{2}

):

CH X_{3} - C \equiv C - CH X_{2} CH X_{3}

, which is pent-2-yne.

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