Answer: A
The ring consists of the four diene carbons and the two dienophile carbons, with the C=C between diene C-2 and C-3. The 1,4 ('para') relation puts the methyl-bearing diene carbon C-2 opposite the ester carbon. Numbering from the ester carbon as C-1 to give the double bond the lowest locant gives the C=C at 3,4, with methyl on C-4. The meta isomer would be the 3-methyl compound.