NEET levelSingle correct optionDifficulty 1 of 3hc002
Heating sodium propanoate, CHX3CHX2COONa, with soda lime (NaOH+CaO) gives mainly
Aethane
Bmethane
Cpropane
Dbutane
Answer: A
Soda-lime decarboxylation removes the carboxylate carbon as carbonate: CHX3CHX2COONa+NaOHCaOΔCHX3CHX3+NaX2COX3. The alkane has one carbon fewer than the acid salt, so ethane forms.