Kolbe electrolysis of aqueous potassium succinate, KOOC-CH2-CH2-COOK, gives at the anode

JEE Main levelSingle correct optionDifficulty 2 of 3hc006

Kolbe electrolysis of aqueous potassium succinate, $KOOC - CH X_{2} - CH X_{2} - COOK$ , gives at the anode

Both carboxylate groups lose

CO X_{2}

at the anode, leaving a diradical

. CH X_{2} - CH X_{2} .

which forms the double bond. So ethene and carbon dioxide form (2 mol

CO X_{2}

per mol of succinate).