Answer: A, B, C
With a very strong base the compound (2-chlorotoluene) loses the hydrogen ortho to Cl (only C-6 has one, since C-2 carries the methyl) and then Cl-, giving a single benzyne. Amide adds at either carbon of the triple bond, giving 2-methylaniline (amine where Cl was) and 3-methylaniline (amine on the neighbouring carbon, cine substitution). So a benzyne is formed, two isomeric products form, and cine substitution occurs; exclusive 2-methylaniline is wrong.