Chlorobenzene (112.5 g) is heated with chloral, CCl3CHO (147.5 g), and concentrated H2SO4 to make DDT, C14H9Cl5 (molar mass 354.5 g mol^-1) with loss of water. The yield is 80 %. The mass of DDT obtained is

JEE Advanced levelSingle correct optionDifficulty 3 of 3hx200

Chlorobenzene ( $112.5 g$ ) is heated with chloral, $CCl X_{3} CHO$ ( $147.5 g$ ), and concentrated $H X_{2} SO X_{4}$ to make DDT, $C X_{14} H X_{9} Cl X_{5}$ (molar mass $354.5 g mo l^{- 1}$ ) with loss of water. The yield is $80 %$ . The mass of DDT obtained is

Equation: 2

C X_{6} H X_{5} Cl

CCl X_{3} CHO

gives DDT +

H X_{2} O

. Moles: chlorobenzene

112.5/112.5 = 1.00

; chloral

147.5/147.5 = 1.00

. Chlorobenzene is limiting (needs 2 per DDT), so 0.50 mol DDT theoretically

= 177.25

g. At 80 percent:

141.8