2-Chlorotoluene is treated with $\mathrm{NaNH}{}_2$ in liquid $\mathrm{NH}{}_3$. Which statements are correct?

With $\mathrm{Cl}$ at C-1 and $\mathrm{CH}{}_3$ at C-2, the only ortho hydrogen is at C-6, so a single benzyne (C1-C6) forms. $\mathrm{NH}{}_2{}^{-}$ adds at C-1 giving 2-methylaniline (NH2 and CH3 ortho) or at C-6 giving 3-methylaniline (NH2 meta to CH3). A para relationship is not possible, so 4-methylaniline is not formed.