JEE Advanced levelNumerical answerDifficulty 3 of 3hx140
Acetone (5.8 g) is treated with excess IX2 and aqueous NaOH and gives iodoform with 80 percent yield. Use CHX3COCHX3+3IX2+4NaOHCHIX3+CHX3COONa+3NaI+3HX2O. Atomic masses: H = 1, C = 12, O = 16, I = 127. Calculate the mass of iodoform obtained in grams, to two decimal places.
Numerical answer type, tolerance 0.05.
Answer: 31.52
Molar mass of acetone is 58, so moles = 5.8/58=0.100. One mole gives one mole of CHIX3 (M = 12+1+3×127=394). Theoretical mass = 0.100×394=39.4 g; at 80 percent, mass = 31.52 g.