A methyl ketone CH3COR is treated with excess I2 and NaOH. The number of moles of I2 consumed per mole of pentan-2-one, CH3COCH2CH2CH3, to form iodoform is

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A methyl ketone $CH X_{3} COR$ is treated with excess $I X_{2}$ and $NaOH$ . The number of moles of $I X_{2}$ consumed per mole of pentan-2-one, $CH X_{3} COCH X_{2} CH X_{2} CH X_{3}$ , to form iodoform is

CH X_{3} COR + 3 I X_{2} + 4 NaOH CHI X_{3} + RCOONa + 3 NaI + 3 H X_{2} O

. All three hydrogens of the

CH X_{3}

next to

C = O

are replaced by iodine (3 mol

I X_{2}

), then

- CI X_{3}

is cleaved by hydroxide to give iodoform and sodium butanoate.