3-Bromotoluene (m-bromotoluene) is treated with $\mathrm{NaNH}{}_2$ in liquid $\mathrm{NH}{}_3$, and the amines formed through all possible benzyne intermediates are isolated. Counting positional isomers of toluidine, the number of different amines formed is

Loss of $\mathrm{HBr}$ using the hydrogen at C-2 gives 3-methylbenzyne (triple bond C-2/C-3) and using the hydrogen at C-4 gives 4-methylbenzyne (triple bond C-3/C-4). Amide addition to 3-methylbenzyne gives 2-methylaniline and 3-methylaniline; addition to 4-methylbenzyne gives 3-methylaniline and 4-methylaniline. The distinct products are o-, m- and p-toluidine, that is 3.