Ethyl ethanoate is treated with excess $\mathrm{CH}{}_3\mathrm{MgBr}$ in dry ether and then with $\mathrm{H}{}_3\mathrm{O}{}^{+}$. Select the correct statements.

The first equivalent of $\mathrm{CH}{}_3\mathrm{MgBr}$ adds to the ester and expels $\mathrm{EtO}{}^{-}$, giving propanone. Ketones are more reactive than esters, so a second equivalent adds at once to give $(\mathrm{CH}{}_3){}_3\mathrm{C}-\mathrm{OMgBr}$. After hydrolysis, 2-methylpropan-2-ol (tertiary) and ethanol are obtained. Propanone cannot be isolated and propan-2-ol would need a hydride, not a methyl, nucleophile.