2-Methylbutane is subjected to free-radical monochlorination ( $Cl X_{2}$ , light). Counting all structurally different monochloro products and counting each pair of enantiomers as two separate products (that is, stereoisomers counted separately), how many distinct monochloro compounds are possible?

Numerical answer type, tolerance 0.5.

Answer: 6

The structures are 1-chloro-2-methylbutane (one stereocentre, 2 enantiomers), 2-chloro-2-methylbutane (1), 2-chloro-3-methylbutane (one stereocentre, 2) and 1-chloro-3-methylbutane (1). Total

= 2 + 1 + 2 + 1 = 6

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2-Methylbutane is subjected to free-radical monochlorination (ClX2​, light). Counting all structurally different monochloro products and counting each pair of enantiomers as two separate products (that is, stereoisomers counted separately), how many distinct monochloro compounds are possible?

Answer: 6

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