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NEET levelSingle correct optionDifficulty 1 of 3hx004

Benzenediazonium chloride is converted into fluorobenzene by treating it with

A $NaF$ with copper powder
B $KF$ in water at 273 K
C $HBF X_{4}$ to form the tetrafluoroborate salt, followed by heating
D $CuF$ (Sandmeyer conditions)

Answer: C

Fluorobenzene is obtained by the Balz-Schiemann reaction:

C X_{6} H X_{5} N X_{2} X^{+} Cl X^{-}

with

HBF X_{4}

gives

C X_{6} H X_{5} N X_{2} X^{+} BF X_{4} X^{-}

, which on heating gives

C X_{6} H X_{5} F + BF X_{3} + N X_{2}

. Direct fluoride exchange or Cu(I) fluoride is not used.

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