Answer: B, D
The ketone shown is 1-cyclopentylpropan-1-one with two alpha carbons: the CH2 of the ethyl group and the ring CH. Removal of a proton from either gives a resonance-stabilised enolate, CHX3CH=C(OX−)X−cyclopentyl or CHX3CHX2C(OX−)=cyclopentylidene. The structures with the carbanion on the terminal CH3 or at a ring carbon beta to the carbonyl are not conjugated with C=O, so they are not enolates.