LDA in THF at $-78^{\circ }$C is added to the ketone shown. At which position does it remove a proton mainly?

The ketone shown is 3-methylbutan-2-one with two alpha carbons: the CH${}_3$ and the tertiary CH. The bulky base LDA at $-78^{\circ }$C acts under kinetic control and removes the more accessible, less hindered proton, giving the less substituted enolate. The carbonyl carbon has no hydrogen, and the two sites are not equivalent.