Answer: B, C
The alkene shown is 3,3-dimethylbut-1-ene. Protonation of C1 follows Markovnikov's rule and gives the secondary 3,3-dimethylbutan-2-yl cation. A 1,2-methyl shift then gives the tertiary 2,3-dimethylbutan-2-yl cation. The primary cations would result from protonation at C2 (anti-Markovnikov) or from unfavourable shifts and are not formed.