Two conformers A and B do not interconvert during the reaction time (their interconversion barrier is far above both reaction barriers). They are present in equilibrium proportions at 298 K, B being $4.0\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$ above A. A reacts irreversibly and completely to PA, and B to PB. With $R=8.314\mathrm{J}\mathrm{mo}{\mathrm{l}}^{-1}{\mathrm{K}}^{-1}$ the final ratio is

1. APA : PB $\approx$ 1 : 1, since both are consumed completely
2. BPA : PB $\approx$ 5 : 1, equal to the conformer population ratio
3. Cfixed only by the transition-state energies, independent of the populations
4. DPB : PA $\approx$ 5 : 1