2-Methylcyclohexan-1-one is treated with one equivalent of LDA in THF at -78 degC. The major enolate is formed by removal of

an H from C-6 (the CH2 side), giving the less substituted C=C

the H from C-2 (the CH bearing the methyl group), giving the more substituted C=C

an H from the methyl group on C-2

an H from C-6 (the CH2 side), giving the less substituted C=C

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2-Methylcyclohexan-1-one is treated with one equivalent of LDA in THF at $- 78^{\circ} C$ . The major enolate is formed by removal of

Athe H from C-2 (the $CH$ bearing the methyl group), giving the more substituted $C = C$
Ban H from the methyl group on C-2
Can H from C-3
Dan H from C-6 (the $CH X_{2}$ side), giving the less substituted $C = C$

Answer: D

LDA is a strong, bulky base and deprotonation is irreversible, so kinetic control operates. The base removes the more accessible hydrogen at C-6 faster. The less substituted (kinetic) enolate results.

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2-Methylcyclohexan-1-one is treated with one equivalent of LDA in THF at −78 ∘C. The major enolate is formed by removal of

Answer: D

More questions on Reaction energy profiles, kinetic vs thermodynamic control

2-Methylcyclohexan-1-one is treated with one equivalent of LDA in THF at $- 78^{\circ} C$ . The major enolate is formed by removal of