Answer: A, B, C
In both reactions an alkyl or aryl group migrates from the carbonyl carbon to the electron-poor nitrogen with retention, giving an isocyanate R−N=C=O. The Curtius route does this by loss of NX2 from the acyl azide. Hydrolysis of the isocyanate loses COX2, so the product has one carbon fewer. Benzamide therefore gives aniline, CX6HX5NHX2, not benzylamine.