Answer: A, B, C
The first three use a strong base, which removes the proton of CHClX3 and then expels chloride to give :CClX2, which attacks the phenoxide ring, the amine nitrogen and the pyrrole C=C respectively. With AlClX3 (a Lewis acid, no base) the electrophile is a CHClX2X+-type species in a Friedel-Crafts reaction, not a carbene.