(S)-2-Methylbutanamide, $\mathrm{CH}{}_3\mathrm{CH}{}_2-\mathrm{CH}(\mathrm{CH}{}_3)-\mathrm{CONH}{}_2$, is treated with $\mathrm{Br}{}_2$ and aqueous $\mathrm{NaOH}$ (Hofmann degradation). The product is

In the Hofmann rearrangement the alkyl group migrates from the carbonyl carbon to nitrogen with retention of configuration, losing the carbonyl carbon as $\mathrm{CO}{}_3{}^{2-}$. Hence $\mathrm{CONH}{}_2$ is replaced by $\mathrm{NH}{}_2$ on the same carbon. The CIP priority order is unchanged ($\mathrm{CONH}{}_2$ and $\mathrm{NH}{}_2$ both outrank ethyl, methyl and H), so (S) gives (S)-butan-2-amine.