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JEE Main levelOne or more correct optionsDifficulty 2 of 3g3098

Which of the following reagent systems can serve as a source of dichlorocarbene, $: CCl X_{2}$ ?

A $CHCl X_{3}$ with $t - BuOK$
B $CCl X_{4}$ with $AlCl X_{3}$
CSodium trichloroethanoate ( $CCl X_{3} COONa$ ) heated in 1,2-dimethoxyethane
D $CH X_{3} Cl$ with aqueous $NaOH$

Answer: A, C

Chloroform with a strong base loses

H X^{+}

and then

Cl X^{-}

. Sodium trichloroethanoate loses

CO X_{2}

to give

CCl X_{3} X^{-}

, which loses

Cl X^{-}

.

CH X_{3} Cl

with

NaOH

undergoes substitution to methanol and cannot give

: CCl X_{2}

because it has no second Cl.

CCl X_{4}

with

AlCl X_{3}

gives

CCl X_{3} X^{+}

rather than a carbene.

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