Answer: D
The compound is barbituric acid. The CH2 hydrogens at C5 lie between two C=O groups; the enolate (equivalently the aromatic-like trione/enol anion) is strongly stabilised, giving pKa about 4.0. The imide N-H hydrogens (pKa above 10) are less acidic, a common error being to assume that N-H is more acidic than C-H.