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JEE Main levelNumerical answerDifficulty 2 of 3g2082

The conjugate acid of piperidine has pKa = 11.1 at 298 K. Using $p K_{a} + p K_{b} = 14$ , find the $p K_{b}$ of piperidine. Give the answer to one decimal place.

Numerical answer type, tolerance 0.05.

Answer: 2.9

For a base and its conjugate acid in water at 298 K,

p K_{a} + p K_{b} = 14

. Therefore

p K_{b} = 14 - 11.1 = 2.9

.

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