Answer: A, B, C
The compound shown is pyridine. Its nitrogen lone pair lies in an sp2 orbital in the ring plane, so it is not part of the sextet (A true). The sextet comes from three C=C/C=N bonds, i.e. 6 pi electrons (B true). Because the lone pair is not used by the pi system, protonation leaves the aromatic sextet intact (C true). The nitrogen is sp2, not sp3, and its lone pair does not enter the sextet (D false).