In a batch esterification, 60.0 kg of ethanoic acid (M = 60) and 46.0 kg of ethanol (M = 46) are charged: $\mathrm{CH}{}_3\mathrm{COOH}+\mathrm{C}{}_2\mathrm{H}{}_5\mathrm{OH}\to \mathrm{CH}{}_3\mathrm{COOC}{}_2\mathrm{H}{}_5+\mathrm{H}{}_2\mathrm{O}$. The ester (M = 88) is isolated in 75.0% yield based on the acid. Define E-factor as (total mass of materials charged minus mass of product isolated) divided by mass of product isolated; solvent and catalyst are ignored. Calculate the E-factor to two decimal places.

Numerical answer type, tolerance 0.01.