Equilibrium constants from E

8 questions on Equilibrium constants from E from the Electrochemistry chapter: 1 NEET level, 4 JEE Main, 3 JEE Advanced. Each one opens with its answer and solution.

• A cell reaction with n = 1 has E deg_cell = 0.1182 V at 298 K. Taking (2.303RT)/(F) = 0.0591 V, the equilibrium constant of the reaction is NEET level
• E deg(Ce^4+/Ce^3+) = 1.61 V and E deg(Fe^3+/Fe^2+) = 0.77 V. For the reaction Fe^2+ + Ce^4+ -> Fe^3+ + Ce^3+ at 298 K, log_10 K (nearest integer) is. Take (2.30... JEE Main level
• A redox reaction involving 2 electrons has equilibrium constant K = 10^10 at 298 K. Taking (2.303RT)/(F) = 0.0591 V, the standard EMF of the corresponding cell ... JEE Main level
• A cell reaction with n = 2 has E deg_cell = 0.0591 V at 298 K. Take (2.303RT)/(F) = 0.0591 V and F = 96500 C mol^-1. Which statements are correct? JEE Main level
• The Daniell cell reaction Zn + Cu^2+ -> Zn^2+ + Cu has E deg = 1.10 V at 298 K. Taking (2.303RT)/(F) = 0.0591 V, the equilibrium constant is of the order of JEE Main level
• E deg(Ag+/Ag) = 0.80 V and E deg for [Ag(NH3)2]+ + e- -> Ag + 2NH3 is 0.37 V at 298 K. The value of log_10 K_f (one decimal) for the formation of [Ag(NH3)2]+ fr... JEE Advanced level
• Given E deg(Fe^3+/Fe^2+) = 0.77 V and E deg(Fe^2+/Fe) = -0.44 V at 298 K. For the disproportionation 3Fe^2+ -> 2Fe^3+ + Fe, the equilibrium constant is of the o... JEE Advanced level
• E deg(Sn^4+/Sn^2+) = 0.15 V and E deg(Fe^3+/Fe^2+) = 0.77 V at 298 K. Consider Sn^2+ + 2Fe^3+ -> Sn^4+ + 2Fe^2+. Take (2.303RT)/(F) = 0.0591 V and F = 96500 C m... JEE Advanced level