A redox reaction involving 2 electrons has equilibrium constant K = 10^10 at 298 K. Taking (2.303RT)/(F) = 0.0591 V, the standard EMF of the corresponding cell is

JEE Main levelSingle correct optionDifficulty 2 of 3ec065

A redox reaction involving 2 electrons has equilibrium constant $K = 1 0^{10}$ at 298 K. Taking $\frac{2.303 RT}{F} = 0.0591 V$ , the standard EMF of the corresponding cell is

E^{\circ} = \frac{0.0591}{n} lo g K = \frac{0.0591}{2} \times 10 = 0.2955 V

. Option B forgets to divide by

n = 2

; option C divides by

n

twice.

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