A mixture of HCl and $\mathrm{CH}{}_3\mathrm{COOH}$ is titrated conductometrically with NaOH. The correct statement(s) is/are

The strong acid reacts first: $\mathrm{H}{}^{+}$ is replaced by $\mathrm{Na}{}^{+}$ and conductance falls, giving the first break at the HCl end point, so (A) is correct and (D) is wrong. Next, the weak acid (its own ionisation suppressed by HCl) is converted into the fully ionised salt $\mathrm{CH}{}_3\mathrm{COONa}$, so conductance rises slowly, giving (B). After the second end point excess $\mathrm{Na}{}^{+}$ and highly mobile $\mathrm{OH}{}^{-}$ cause a steep rise, giving (C). Two end points are thus obtained from one titration.