In the electrolysis of aqueous NaCl (brine) with inert electrodes, Cl2 is obtained at the anode although E deg(O2,H+/H2O

Question

In the electrolysis of aqueous NaCl (brine) with inert electrodes, Cl2 is obtained at the anode although E deg(O2,H+/H2O) = 1.23 V is lower than E deg(Cl2/Cl-) = 1.36 V. This is because

Accepted Answer

oxygen evolution has a large overpotential on the electrode surface

Answer

chloride ion is a stronger reducing agent than water

Answer

sodium ions migrate to the anode and block water oxidation

Answer

the concentration of water is too low in brine

In the electrolysis of aqueous NaCl (brine) with inert electrodes, $Cl X_{2}$ is obtained at the anode although $E^{\circ} (O X_{2}, H X^{+} / H X_{2} O) = 1.23 V$ is lower than $E^{\circ} (Cl X_{2} / Cl X^{-}) = 1.36 V$ . This is because

Answer: A

In the electrolysis of aqueous NaCl (brine) with inert electrodes, ClX2​ is obtained at the anode although E∘(OX2​,HX+/HX2​O)=1.23 V is lower than E∘(ClX2​/ClX−)=1.36 V. This is because

Answer: A

In the electrolysis of aqueous NaCl (brine) with inert electrodes, $Cl X_{2}$ is obtained at the anode although $E^{\circ} (O X_{2}, H X^{+} / H X_{2} O) = 1.23 V$ is lower than $E^{\circ} (Cl X_{2} / Cl X^{-}) = 1.36 V$ . This is because