JEE Main levelSingle correct optionDifficulty 2 of 3ec178
A conductivity cell filled with 0.1 M KCl (κ=1.29Sm−1) has a resistance of 85Ω. When the same cell is filled with an unknown solution the resistance is 210Ω. The conductivity of the unknown solution is
A0.522Sm−1
B3.19Sm−1
C1.92Sm−1
D6.14×10−3Sm−1
Answer: A
Cell constant G∗=κR=1.29×85=109.65m−1. For the unknown, κ=G∗/R=109.65/210=0.522Sm−1. Equivalently κ2=κ1R1/R2; inverting the resistance ratio gives the wrong value 3.19.