NEET levelSingle correct optionDifficulty 1 of 3ec099
The reduction potential of a hydrogen electrode (pHX2=1bar) in a buffer of pH 5 at 298 K is (take 2.303RT/F=0.0591V)
A−0.296V
B−0.591V
C+0.296V
D−0.148V
Answer: A
For 2HX++2eX−HX2 at 1 bar, E=0−20.0591log[HX+]21=−0.0591pH. At pH 5, E=−0.0591×5=−0.2955≈−0.296V. The potential falls by 0.0591 V for every unit rise in pH.