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NEET levelSingle correct optionDifficulty 1 of 3df113

The number of unpaired electrons in $Mn X^{2 +}$ ( $Z = 25$ ) is:

A5
B3
C4
D0

Answer: A

Mn is

[Ar] 3 d^{5} 4 s^{2}

. Removing the two 4s electrons gives

3 d^{5}

, in which each d orbital holds one electron, so

n = 5

.

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