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NEET levelSingle correct optionDifficulty 1 of 3df112

The spin-only magnetic moment of $Cu X^{2 +}$ ( $Z = 29$ ) is, using $μ = n (n + 2)$ BM:

A $3.87 BM$
B $0 BM$
C $2.83 BM$
D $1.73 BM$

Answer: D

Cu X^{2 +}

is

3 d^{9}

with

n = 1

unpaired electron.

μ = 1 \times 3 = 1.73 BM

.

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