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The oxidation state of chromium in $K X_{2} Cr X_{2} O X_{7}$ is

A $+ 3$
B $+ 6$
C $+ 7$
D $+ 12$

Answer: B

Let the oxidation state of Cr be

x

. Then

2 (+ 1) + 2 x + 7 (- 2) = 0

, so

2 x = 12

and

x = + 6

.

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