JEE Advanced levelSingle correct optionDifficulty 3 of 3df051
In the reaction 2MnOX4X−+5CX2OX4X2−+16HX+2MnX2++10COX2+8HX2O in acidic medium, the initial rate is slow but increases as the reaction proceeds. The autocatalyst, and the volume of COX2 at STP produced from 40.0mL of 0.100MKMnOX4 with excess oxalate, are
AMnX2+; 0.224L
BHX+; 0.448L
CMnX2+; 0.448L
DMnX2+; 0.0896L
Answer: C
The product MnX2+ catalyses its own formation (via Mn(III) intermediates), so the rate rises. Moles of MnOX4X− = 0.0400×0.100=0.00400; the ratio COX2:MnOX4X− is 10:2 = 5, so COX2 = 0.0200 mol. Volume = 0.0200×22.4=0.448L.