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JEE Main levelSingle correct optionDifficulty 2 of 3df015

The spin-only magnetic moment of gaseous $Cr X^{2 +}$ ( $Z = 24$ ) is

A $3.87 BM$
B $2.83 BM$
C $4.90 BM$
D $5.92 BM$

Answer: C

Cr X^{2 +}

is

[Ar] 3 d^{4}

, giving 4 unpaired electrons.

μ = 4 \times 6 = 24 = 4.90 BM

.

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