Isomerism: structural and stereoisomerism

27 questions on Isomerism: structural and stereoisomerism from the Coordination Compounds chapter: 5 NEET level, 11 JEE Main, 11 JEE Advanced. Each one opens with its answer and solution.

• Which of the following ligands can give rise to linkage isomerism in its complexes? NEET level
• [Co(NH3)5Cl]SO4 and [Co(NH3)5SO4]Cl are related as NEET level
• [Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]Cl2.H2O are an example of NEET level
• The existence of cis and trans forms of square planar [Pt(NH3)2Cl2] is an example of NEET level
• The total number of stereoisomers of the octahedral complex ion [Co(en)3]^3+ is NEET level
• Assuming an octahedral geometry, the number of geometrical isomers of [Co(NH3)3Cl3] is JEE Main level
• The total number of stereoisomers (geometrical plus optical) of the octahedral ion [Co(en)2Cl2]+ is JEE Main level
• Which pair consists only of ambidentate ligands? JEE Main level
• Select the pairs that are correctly matched with the type of isomerism they illustrate. One or more options may be correct. JEE Main level
• Which of the following can show geometrical isomerism? Assume square planar geometry for the Pt(II) complex and octahedral geometry for the Co(III) complexes. JEE Main level
• Which of the following octahedral species are optically active? One or more options may be correct. JEE Main level
• Assertion: tetrahedral [NiCl2Br2]^2- does not show geometrical isomerism. Reason: in a tetrahedron every ligand position is adjacent to every other position, so... JEE Main level
• Match the complex in Column I with the isomerism it can show in Column II. Column I: P [Co(NH3)5Cl]SO4; Q [Cr(H2O)6]Cl3; R [Co(NH3)5(NO2)]Cl2; S [Cu(NH3)4][PtCl... JEE Main level
• The number of geometrical isomers of the square planar complex [Pt(NH3)(py)ClBr] (py = pyridine, monodentate) is JEE Main level
• Considering both geometrical and linkage isomerism (octahedral, no optical isomers here), the total number of isomers of [Co(NH3)4(NO2)Cl]+ in which NO2- may bi... JEE Main level
• Which of the following octahedral ions does not show any stereoisomerism? JEE Main level
• The octahedral complex [M(AB)2c2] contains two identical unsymmetrical bidentate ligands AB (each with two different donor atoms A and B) and two identical mono... JEE Advanced level
• The total number of stereoisomers of the octahedral ion [Co(en)(NH3)2Cl2]+ (en = symmetrical bidentate) is JEE Advanced level
• [Co(en)2(NO2)Cl]+ contains the ambidentate NO2- (bound through N or O). Counting geometrical, optical and linkage isomers together (octahedral, en symmetrical b... JEE Advanced level
• An octahedral complex [Co(gly)3] contains three unsymmetrical bidentate glycinate ligands (N and O donors). The total number of stereoisomers (geometrical plus ... JEE Advanced level
• Consider the octahedral cation [Co(en)2Cl2]+ and the related ions. Which statements are correct? One or more options may be correct. JEE Advanced level
• Assuming an octahedral geometry for the six-coordinate species and square planar geometry where stated, which statements about the number of geometrical isomers... JEE Advanced level
• Which of the following octahedral complex ions are optically active? One or more options may be correct (en = symmetrical bidentate; EDTA^4- = hexadentate). JEE Advanced level
• Square planar [Pt(NH3)2Cl2] exists as isomers X and Y. Only X reacts with oxalic acid, replacing both Cl- to give [Pt(NH3)2(C2O4)], whereas Y does not (the bide... JEE Advanced level
• Which statement about the square planar complex [Pt(NH3)(py)ClBr] (py = pyridine) is correct? JEE Advanced level
• Assertion: square planar [Pt(NH3)(py)ClBr] has four different ligands and therefore must exist as pairs of optical isomers. Reason: a square planar complex with... JEE Advanced level
• The octahedral cation [Co(NH3)4(NO2)2]+ contains two NO2- ligands, each of which may be bound through N (nitro) or O (nitrito). Treating a cis or trans arrangem... JEE Advanced level