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JEE Main levelSingle correct optionDifficulty 2 of 3cc197

In the 18-electron anion $[Co (CO) X_{4}] X^{-}$ , the oxidation state of cobalt and the valence-electron count (metal electrons plus two per CO, including charge) are:

A $- 1$ , 16
B $+ 1$ , 18
C $- 1$ , 18
D $0$ , 17

Answer: C

Charge

- 1

equals

x + 0

, so

x = - 1

. Count =

9 + 1 + 4 \times 2 = 18

. Thus Co is in the

- 1

state with an 18-electron configuration.

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