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JEE Main levelSingle correct optionDifficulty 2 of 3cc130

Violet $CrCl X_{3} \cdot 6 H X_{2} O$ gives 3 mol $AgCl$ per mole with excess $AgNO X_{3}$ and its coordination number is 6. A green isomer of the same composition gives 2 mol $AgCl$ per mole. The green isomer is

A $[Cr (H X_{2} O) X_{6}] Cl X_{3}$
B $[Cr (H X_{2} O) X_{3} Cl X_{3}] \cdot 3 H X_{2} O$
C $[Cr (H X_{2} O) X_{4} Cl X_{2}] Cl \cdot 2 H X_{2} O$
D $[Cr (H X_{2} O) X_{5} Cl] Cl X_{2} \cdot H X_{2} O$

Answer: D

Two free chlorides means one chloride is bound. With coordination number 6 the sphere holds

5 H X_{2} O + 1 Cl X^{-}

, and the sixth water is lattice water. This is

[Cr (H X_{2} O) X_{5} Cl] Cl X_{2} \cdot H X_{2} O

.

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