JEE Advanced levelSingle correct optionDifficulty 3 of 3cc106
An octahedral complex KXx[CrFX6] has chromium in the +2 or +3 state, F- is a weak-field ligand, and the spin-only moment is 4.90 BM. The formula and name are
4.90 BM needs n=4 unpaired electrons. High-spin d4 (CrX2+) has 4, while d3 (CrX3+) has 3 (μ=3.87). So Cr is +2 and the anion charge is 2−6=−4, giving KX4[CrFX6].