Match the species in Column I with the oxidation state of the metal in Column II. Column I: P [Fe(CN)6]^4-; Q [Ni(CO)4]; R [V(CO)6]^-; S [Cr(NH3)5Cl]^2+. Column II: 1 -1; 2 0; 3 +2; 4 +3.

JEE Main levelSingle correct optionDifficulty 2 of 3cc068

Match the species in Column I with the oxidation state of the metal in Column II. Column I: P $[Fe (CN) X_{6}] X^{4 -}$ ; Q $[Ni (CO) X_{4}]$ ; R $[V (CO) X_{6}] X^{-}$ ; S $[Cr (NH X_{3}) X_{5} Cl] X^{2 +}$ . Column II: 1 $- 1$ ; 2 $0$ ; 3 $+ 2$ ; 4 $+ 3$ .

x - 6 = - 4

gives

+ 2

. Q: CO is neutral, so 0. R:

x + 0 = - 1

gives

- 1

. S:

x - 1 = + 2

gives

+ 3

. So P-3, Q-2, R-1, S-4.