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JEE Advanced levelSingle correct optionDifficulty 3 of 3cc095

0.100 mol of (Cr coordination number 6) gives 14.35 g of AgCl with excess (Ag = 108, Cl = 35.5). The IUPAC name of the complex and the number of geometrical isomers of its cation are

  1. Atetraaquadichloridochromium(III) chloride; 2
  2. Btetraaquadichloridochromium(III) chloride; 1
  3. Ctetraaquadichloridochromium(III) chloride; 3
  4. Ddichloridotetraaquachromium(III) chloride; 2

Answer: A

14.35 g is 0.100 mol of AgCl, so one Cl per formula unit is ionic and two Cl are bound: . It is named tetraaquadichloridochromium(III) chloride (aqua before chlorido). The cation is of type and has cis and trans forms, so 2 geometrical isomers.
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