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JEE Main levelOne or more correct optionsDifficulty 2 of 3cc065

Take $[NiCl X_{4}] X^{2 -}$ as tetrahedral and $[Ni (CN) X_{4}] X^{2 -}$ as square planar. Select the correct statements.

ABoth complexes use $s p^{3}$ hybridisation
B $[Ni (CN) X_{4}] X^{2 -}$ is diamagnetic
C $[NiCl X_{4}] X^{2 -}$ is paramagnetic with two unpaired electrons
DNickel is in the +2 oxidation state in both complexes

Answer: B, C, D

Ni(II) is

d^{8}

in both (

x - 4 = - 2

). In the tetrahedral chloro complex (weak field) two electrons stay unpaired. The strong field CN- pairs all electrons into a

d s p^{2}

square planar arrangement, so it is diamagnetic. Hybridisation is

s p^{3}

for the first but

d s p^{2}

for the second.

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