JEE Advanced levelNumerical answerDifficulty 3 of 3el218
A municipal reservoir holds 3.6×106 L of water (density 1.00gmL−1). Drinking water is treated to 0.20 ppm of ClX2 by mass (that is, 0.20g of ClX2 per 106g of water). The chlorine is supplied by bleaching powder that contains 35% available chlorine by mass. Calculate the mass of bleaching powder needed, in kg, to two decimal places.
Numerical answer type, answer in kg, tolerance 0.01.
Answer: 2.06 kg
Mass of water = 3.6×106L×1000gL−1=3.6×109g. Chlorine needed = 0.20×3.6×109/106=720g=0.72kg. Bleaching powder = 0.72/0.35=2.06kg.