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JEE Advanced levelSingle correct optionDifficulty 3 of 3el189

A sample of $445 g$ of tristearin (molar mass $890$ g/mol) is saponified with NaOH (Na = 23, glycerol molar mass $92$ g/mol). The mass of NaOH required and the mass of glycerol obtained are, respectively,

A $40 g$ and $92 g$
B $20 g$ and $46 g$
C $60 g$ and $138 g$
D $60 g$ and $46 g$

Answer: D

Moles of tristearin =

445/890 = 0.500

. NaOH needed =

3 \times 0.500 = 1.50

mol =

60 g

. Glycerol =

1 \times 0.500

mol

\times 92 = 46 g

.

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