JEE Main levelOne or more correct optionsDifficulty 2 of 3ck141
Which statements about the Arrhenius equation k=Ae−Ea/RT are correct (treat A and Ea as temperature independent)?
AA plot of lnk against 1/T is a straight line with a negative slope
BAs T→∞, k→A
CA reaction with larger Ea shows a larger relative increase in k for the same rise in temperature
DA catalyst changes ΔH of the reaction by changing Ea
Answer: A, B, C
lnk=lnA−Ea/RT is linear in 1/T with slope −Ea/R<0. Since dlnk/dT=Ea/RT2, larger Ea gives larger sensitivity. As T→∞ the exponential tends to 1 so k→A. A catalyst lowers Ea but leaves ΔH unchanged, so the third statement is false.