At 300 K, the fraction of molecular collisions with energy at least E_a=39 kJ mol^-1 is xx10^-7. Find x to two decimal places. Use R=8.314 J mol^-1K^-1.

JEE Main levelNumerical answerDifficulty 2 of 3ck140

At 300 K, the fraction of molecular collisions with energy at least $E_{a} = 39 kJ mo l^{- 1}$ is $x \times 1 0^{- 7}$ . Find $x$ to two decimal places. Use $R = 8.314 J mo l^{- 1} K^{- 1}$ .

Numerical answer type, tolerance 0.03.

Fraction

= e^{- E_{a} / RT}

E_{a} / RT = \frac{39000}{8.314 \times 300} = 15.636

, so the fraction is

e^{- 15.636} = 1.62 \times 1 0^{- 7}